For this case we have the following system of equations:
[tex]y=-x-2\\y=x[/tex]
If we substitute the second equation in the first we have:
[tex]x=-x-2\\[/tex]
[tex]x + x= -2\\2x = -2[/tex]
[tex]x=\frac {-2} {2}\\x=-1[/tex]
So:
[tex]y = -1[/tex]
Thus, the lines intersect at:[tex](x, y):(-1,-1)[/tex]
Answer:
See attached image
[tex](x, y):(- 1, -1)[/tex]
