Answer with Step-by-step explanation:
Khairul deposited $600 in a bank at the end of 2010 at the rate of 3 % per annum simple interest.
simple interest=[tex]\dfrac{P\times r\times t}{100}[/tex]
where P is the principal amount
r is the interest rate and t is the time
interest got till the end of 2011= [tex]\dfrac{600\times 3\times 1}{100}[/tex]
= $ 18
Khairul deposited $400 in the same bank at the end of 2011.
At the end of 2011 total amount in his bank= $(600+18+400)
= $1018
Interest he got from end of 2011 till end of 2013=[tex]\dfrac{1018\times 3\times 2}{100}[/tex]
= $ 61.08
Total amount in his bank at the end of 2013=$(1018+61.08)
= $ 1079.08
Hence, total amount Khairul has in his bank at the end of 2013 is:
$ 1079.08
