Complete the following conversions between SI units.
(a) 612 g = _____________mg
(b) 8.160 m= ____________cm
(c) 3779 µg= ____________g
(d) 781 mL = ____________L
(e) 4.18 kg = ____________g
(f) 27.8 m =_____________km
(g) 0.13 mL=____________L
(h) 1738 km = ___________m
(i) 1.9 Gg= _____________g

Respuesta :

Answer:

a) 612000 mg

b) 816 cm

c) 3.779 E-7 g

d) 0.781 L

e) 4180 g

f) 0.0278 Km

g) 1.3 E-4 L

h) 1738000 m

i) 1900000000 g

Explanation:

a) 612 g * ( 1000mg / g ) = 612000 mg

b) 8.160 m * ( 100 cm / m ) = 816 cm

c) 3779µg * ( 0.0001 µg /  ) * ( g / 1000000 µg ) = 3.779 E-7 g

d) 781 mL * ( L / 1000 mL) = 0.781 L

e) 4.18 Kg * ( 1000g / Kg) = 4180 g

f) 27.8 m * ( Km / 1000 m ) = 0.0278 Km

g) 0.13 mL * ( L / 1000mL ) = 1.3 E-4 L

h) 1738 Km * ( 1000 m / Km ) = 1738000 m

i) 1.9 Gg * ( 1 E9 g / Gg ) = 1900000000 g

Answer:

For a:  [tex]612g=6.12\times 10^5mg[/tex]

For b:  8.160 m = 816.0 cm

For c:  [tex]3779\mu g=3.779\times 10^{-3}g[/tex]

For d:  781 mL = 0.781 L

For e:  4.18 kg = 4180 g

For f:  27.8 m = 0.0278 km

For g:  [tex]0.13mL=1.3\times 10^{-4}L[/tex]

For h:  [tex]1738km=1.738\times 10^6m[/tex]

For i:  [tex]1.9Gg=1.9\times 10^9g[/tex]

Explanation:

Units is defined as the standard which is used to make comparisons between the measurements.

For the given options:

  • For a:

The conversion factor used is:

[tex]1g=1\times 10^{3}mg[/tex]

So, [tex]612g\times \frac{10^3mg}{1g}=6.12\times 10^5mg[/tex]

  • For b:

The conversion factor used is:

[tex]1m=100cm[/tex]

So, [tex]8.160m\times \frac{100cm}{1m}=816.0cm[/tex]

  • For c:

The conversion factor used is:

[tex]1g=1\times 10^{6}\mu g[/tex]

So, [tex]3779\mu g\times \frac{1g}{10^6\mu g}=3.779\times 10^{-3}g[/tex]

  • For d:

The conversion factor used is:

[tex]1L=1000mL[/tex]

So, [tex]781mL\times \frac{1L}{1000mL}=0.781L[/tex]

  • For e:

The conversion factor used is:

[tex]1kg=1000g[/tex]

So, [tex]4.18kg\times \frac{1000g}{1kg}=4180g[/tex]

  • For f:

The conversion factor used is:

[tex]1km=1000m[/tex]

So, [tex]27.8m\times \frac{1km}{1000m}=0.0278km[/tex]

  • For g:

The conversion factor used is:

[tex]1L=1000mL[/tex]

So, [tex]0.13mL\times \frac{1L}{1000mL}=1.3\times 10^{-4}L[/tex]

  • For h:

The conversion factor used is:

[tex]1km=1000m[/tex]

So, [tex]1738km\times \frac{1000m}{1km}=1.738\times 10^6m[/tex]

  • For i:

The conversion factor used is:

[tex]1Gg=10^9g[/tex]

So, [tex]1.9Gg\times \frac{10^9g}{1Gg}=1.9\times 10^9g[/tex]