Respuesta :
Answer: the correct answer is 7.8026035971 x 10^(-13) joule
Explanation:
Use Energy Conservation. By ``alpha decay converts'', we mean that the parent particle turns into an alpha particle and daughter particles. Adding the mass of the alpha and daughter radon, we get
m = 4.00260 u + 222.01757 u = 226.02017 u .
The parent had a mass of 226.02540 u, so clearly some mass has gone somewhere. The amount of the missing mass is
Delta m = 226.02540 u - 226.02017 u = 0.00523 u ,
which is equivalent to an energy change of
Delta E = (0.00523 u)*(931.5MeV/1u)
Delta E = 4.87 MeV
Converting 4.87 MeV to Joules
1 joule [J] = 6241506363094 mega-electrón voltio [MeV]
4 mega-electrón voltio = 6.40870932 x 10^(-13) joule
4.87 mega-electrón voltio = 7.8026035971 x 10^(-13) joule
The required amount of energy released due to loss of mass is [tex]7.80 \times 10^{-13} \;\rm J[/tex].
Given data:
Einstein's mass - energy relation is given as, [tex]E = mc^{2}[/tex].
Here,
m is the mass and c is the speed of light.
Use Energy Conservation. By ``alpha decay converts'', we mean that the parent particle turns into an alpha particle and daughter particles. Adding the mass of the alpha and daughter radon, we get
m = 4.00260 u + 222.01757 u
m = 226.02017 u .
The parent had a mass of 226.02540 u, so clearly some mass has gone somewhere. The amount of the missing mass is,
[tex]\Delta m = 226.02540\;\rm u - 226.02017\;\rm u\\\\\Delta m = 0.00523 \;\rm u[/tex]
Then the equivalent change in the energy is given as,
[tex]\Delta E = (0.00523 \;\rm u) \times (931.5\;\rm MeV/u)\\\Delta E = 4.87 \;\rm MeV[/tex]
Converting 4.87 MeV to Joules as,
[tex]1 \;\rm J= 6.242 \times 10^{12}\;\rm MeV\\4.87 \;\rm MeV = \dfrac{4.87}{ 6.242 \times 10^{12}}\;\rm J\\\\ =7.80 \times 10^{-13} \;\rm J[/tex]
Thus, we can conclude that the required amount of energy released due to loss of mass is [tex]7.80 \times 10^{-13} \;\rm J[/tex].
Learn more about the Equivalent energy here:
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