Respuesta :
Answer:
P=681.07mmHg
Explanation:
gas law:
(V1 * P1 ) / T1 = (V2 * P2 ) / T2
⇒ P2 = ( V1 * P1 * T2) / ( T1 * V2)
∴ V1 = 4.6L;
P1 = 365mmHg * 0.001315 atm / 1 mmHg = 0.48 atm
T2 = 36°C + 273 = 309 K
T1 = 20 °C + 273 = 293 K
V2 = 2.6 L
⇒ P2 = ((4.6 L) * (0.48 atm) * (309 K)) / ((293 K) * (2.6 L))
⇒P2 = 0.895 atm ( 681.07 mmHg)
when compressing the gas inside the cylinder, the internal pressure increases
Answer:
P2 = 681.03 mmHg
Explanation:
Before moving any further, let's bring out all the parameters stated in the question.
Initial Volume (V1) = 4.60L
Initial Pressure (P1) = 365 mmHg
Initial Temperature (T1) = 20 C + 273 = 293K (Converting to Kelvin Temperature)
Final Temperature (T2) = 36 C + 273 = 309K (Converting to Kelvin Temperature)
Final Volume (V2) = 2.60 L
Final Pressure (P2) = ?
The problem stated three gas parameters (volume, pressure and temperature), hence we are going to use the general gas equation because it is the formular that defines the relationship between the three gas parameters.
It is given as;
[tex]\frac{P1V1}{T1} = \frac{P2V2}{T2}[/tex]
Making P2 subject of interest, we are left with;
[tex]P2 = \frac{P1V1T2}{V2T1}[/tex]
P2 = (365 * 4.6 * 309) / (2.6 * 293)
P2 = 681.03 mmHg
