A force of 45 newtons is applied on an object, moving it 12 meters away in the same direction as the force. What is the magnitude of work done on the object by this force?

Respuesta :

If the applied force is in the same direction as the object's displacement, the work done on the object is:

W = Fd

W = work, F = force, d = displacement

Given values:

F = 45N

d = 12m

Plug in and solve for W:

W = 45(12)

W = 540J

Work done= 540J

What is work done ?

The work done by a force can be defined as the product of the displacement of an object and the component of the applied force which is in the direction of the object's displacement.

Work done = Fs cos (theta )

Work done= ?

F = force = 45 N

s = displacement = 12 m

Given values:

F = 45N

d = 12m

Work done = 45 * 12 * cos 0°

Work done= 540J

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