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A contractor can pay his crew at most $425 a day. It costs $80 each day to operate the forklift and $65 a day for each crew member. Write an inequality to represent the contractor's budget for the day.
A. 80x − 65 ≤ 425
B. 80x − 65 ≥ 425
C. 80 + 65x ≤ 425
D. 80 + 65x ≥ 425

Respuesta :

Answer:

80 + 65x ≤ 425

Step-by-step explanation:

First of all we know that the 425 must be greater than or equal to the other side, so the symbol to show that would be ≤. We also know that the forklift is a fixed price by the words 'each day'. And the to hire a single crew member would be $65 unless there are more crew workers, which would be multiplied with the 65.

The third option is correct. C. 80 + 65x ≤ 425

The following information should be considered:

  • The 425 should be greater or equivalent to the other side so the symbol should be used i.e.  ≤.
  • Also we know that forklift should be the fixed price by the words each day.
  • And, for hiring the single crew member i.e. $65 until there should be more crew workers so the same multiplied with the 65.

Learn more: brainly.com/question/17429689

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