Respuesta :
The closest answer I have found for this to be correct is 0.54 I divided 112 and 200 and got 0.56
Answer:
Option A
Explanation:
Given -
Total population of rats [tex]= 200[/tex]
Out of the total population, number of rats with brown fur [tex]= 112[/tex]
Thus , the frequency of brown fur rats
[tex]= \frac{112}{200} \\= 0.56[/tex]
It is also given that the brown fur rats are dominant to gray fur rats.
As per Hardy Weinberg's equation,
Frequency of dominant rats is given by [tex]p^2[/tex]
and here
[tex]p^2 + 2pq = 0.56[/tex]
Thus,
Frequency of homozygous recessive gray rat
[tex]p^2 + q^2+2pq = 1\\\\q^ 2 = 1-0.56\\ q^ 2 = 0.44\\q = 0.663[/tex]
Hence,
[tex]p = 1-q\\= 1-.663\\\\= 0.337\\[/tex]
frequency of homozygous dominant rats
[tex]= p^2\\= 0.337^2\\= 0.1135[/tex]
Hence, option A is correct