Answer:
The thickness of the foil is 0.01450 mm
Explanation:
1 ft = 30.48 cm
So area of Al foil is [tex](30.48)^{2}cm^{2}[/tex]
if thickness of foil is d cm then volume of Al foil is [tex](30.48)^{2}dcm^{3}[/tex]
We know, [tex]density = \frac{mass}{volume}[/tex]
Here density of Al is 2.699 [tex]g/cm^{3}[/tex] and mass of foil is 3.636 g.
So volume of foil is [tex]\frac{3.636 g}{2.699g/cm^{3}}[/tex] or [tex]\frac{3.636}{2.699}cm^{3}[/tex]
So, [tex](30.48)^{2}d=\frac{3.636}{2.699}[/tex]
or, d = 0.001450
So thickness of foil is 0.001450 cm or 0.01450 mm
