Answer:
m = 63.7 kg
Explanation:
As we know that when mass connected to the bungee cord stretch the string then the gravitational potential energy of the person will convert into potential energy of the string at the end
now here we know that when person jump from the top and reach at the end then loss in gravitational potential energy is given as
[tex]U = mgH[/tex]
[tex]U = m(9.81)(200)[/tex]
[tex]U = 1962 m[/tex]
now when it is at the end of the motion stretch in the string will be
[tex]x = 200 - 100 = 100 m[/tex]
now potential energy of string is given as
[tex]U_{spring} = \frac{1}{2}kx^2[/tex]
[tex]U_{spring} = \frac{1}{2}(25)(100^2)[/tex]
now by energy conservation we have
[tex]1962 m = \frac{1}{2}(25)(100^2)[/tex]
[tex]m = 63.7 kg[/tex]
