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A tank contains 9000 L of pure water. Brine that contains 40 g of salt per liter of water is pumped into the tank at a rate of 25 L/min. The concentration of salt after t minutes (in grams per liter) is C(t) = 40t 360 + t . As t → ∞, what does the concentration approach? g

Respuesta :

Explanation:

The concentration of salt after t minutes is given by :

[tex]C(t)=\dfrac{40t}{360+t}[/tex]

A tank contains 9000 L of pure water. Brine that contains 40 g of salt per liter of water is pumped into the tank at a rate of 25 L/min.

We need to find the concentration approach at [tex]t\rightarrow \infty[/tex]

So, [tex]\lim_{t \to \infty}C(t)=\dfrac{40t}{360+t}[/tex]

[tex]\lim_{t \to \infty}C(t)=\dfrac{40}{\dfrac{360}{t}+1}[/tex]

Put [tex]t=\infty[/tex]

[tex]\lim_{t \to \infty}C(t)=\dfrac{40}{\dfrac{360}{\infty}+1}[/tex]

Since, [tex]\dfrac{360}{\infty}=0[/tex]

C(t) = 40 g/L

So, at [tex]t\rightarrow \infty[/tex] the concentration approaches to 40 g/L. Hence, this is the required solution.