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Suppose that light from a laser with wavelength 633 nm is incident on a thin slit of width 0.500 mm. If the diffracted light projects onto a screen at distance 1.50 m, what is the distance y2 from the center of the diffraction pattern to the dark band with m=2?

Respuesta :

Explanation:

It is given that,

Wavelength, [tex]\lambda=633\ nm=633\times 10^{-9}\ m[/tex]

Slit width, [tex]a=0.5\ mm=0.0005\ m[/tex]

Order, m = 2

If the diffracted light projects onto a screen at distance 1.50 m, L = 1.5 m

For the diffraction of light,

[tex]y=\dfrac{m\lambda L}{a}[/tex]

[tex]y=\dfrac{2\times 633\times 10^{-9}\times 1.5}{0.0005}[/tex]

y = 0.0037 m

So, the distance from the center of the diffraction pattern to the dark band is 0.0037 meters. Hence, this is the required solution.

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