Answer:
6.3 m/s
Explanation:
m = mass of the block = 1.10 kg
k = spring constant of the spring
x = stretch in the spring = 0.2 m
t = time taken by block to come to zero speed first time = 0.100 s
T = Time period of oscillation
Time period of oscillation is given as
T = 2t
T = 2 (0.1)
T = 0.2 s
Time period is also given as
[tex]T = 2\pi \sqrt{\frac{m}{k}}[/tex]
[tex]0.2 = 2(3.14) \sqrt{\frac{1.10}{k}}[/tex]
k = 1084.6 N/m
v = maximum speed of the block
using conservation of energy
Maximum kinetic energy = Maximum spring potential energy
(0.5) m v² = (0.5) k x²
m v² = k x²
(1.10) v² = (1084.6) (0.2)²
v = 6.3 m/s
