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A technical machinist is asked to build a cubical steel tank that will hold 480L of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest 0.001m .

Respuesta :

Answer:

0.78299 m

Step-by-step explanation:

It is given that the steel tank will hold 480 l

We know that [tex]1 L=\frac{1}{1000}=0.001 m^3[/tex]

So 480 L =480×0.001=0.480 [tex]m^3[/tex]

We know that volume [tex]V=a^3[/tex]

So [tex]a=V^{\frac{1}{3}}=0.480^{\frac{1}{3}}=0.78299\ m[/tex]

So the 0.78299 meter length will be smallest possible length possible inside the tank

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