Answer:
int SmallestNumber(int num1, int num2, int num3){
int smallest;
if (num1 >num2){
smallest=num2;
}
else {
smallest=num1;
}
if(smallest <num3){
smallest=num3;
}
}
int LargestNumber(int num1, int num2, int num3){
int largest;
if (num1 <num2){
largest=num2;
}
else {
largest=num1;
}
if(largest>num3){
largest=num3;
}
}
void main(){
int num1,num2,num3;
printf("enter values");
scanf("%d%d%d",&num1,&num2,&num3);
int smallest=SmallestNumber(num1,num2,num3);
int largest=LargestNumber(num1,num2,num3);
}
Explanation:
we are comparing first two numbers and finding largest among those. After getting largest comparing that with remaining if it is greater then it will be largest of three. Same logic applicable to smallest also
The program which evaluates the values in a function and outputs the largest and smallest values written in python 3 is given as follows :
def smallest(num1, num2, num3):
#initialize a function which takes 3 parameters
if (num1 < num2):
#compares the first and second values
smallest = num1
#assign the smaller value to a variable
else :
smallest = num2
if num3 < smallest:
smallest = num3
print('smallest integer : ', smallest)
#displays the minimum of the values
def largest(num1, num2, num3):
#initialize a function that takes 3 parameters
if (num1 > num2):
#compares the first two values
largest = num1
#assign the larger to another variable
else :
largest = num2
if num3 > largest:
#compare the varibale with the third value
largest = num3
print('largest integer : ', largest)
#displays the largest of the 3 variables.
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