Answer:The formulas of ionic compounds are:
a)[tex]CuBr[/tex]
b)[tex]Mn_2O_3[/tex]
c)[tex]Hg_2I_2[/tex]
d)[tex]Mg_3(PO_4)_2[/tex]
Explanation:
Formulas for the an ionic compounds is determine by:
Criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
(a) Copper bromide :Given that it contains [tex]Cu^+[/tex] ion.
[tex]Cu^++Br^-\rightarrow CuBr[/tex]
(b) Manganese oxide : Given that it contains [tex]Mn^{3+}[/tex] ion.
[tex]Mn^{3+}+O^{2-}\rightarrow Mn_2O_3[/tex]
(c)Mercury iodide :Given that it contains [tex]Hg_2^{2+}[/tex]
[tex]Hg_2^{2+}+I^-\rightarrow Hg_2I_2[/tex]
(d) Magnesium phosphate :Given that it contains [tex]PO_4^{3-}[/tex]
[tex]Mg^{2+}+PO_4^{3-}\rightarrow Mg_3(PO_4)_2[/tex]
