An elastic band is hung on a hook and a mass is hung on the lower end of the band. When the mass is pulled downward and then released, it vibrates vertically. The equation of motion is s = 6 cos(t) + 3 sin(t), t ≥ 0, where s is measured in centimeters and t in seconds. (Take the positive direction to be downward.) (a) Find the velocity and acceleration at time t. g

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Explanation:

An elastic band is hung on a hook and a mass is hung on the lower end of the band. When the mass is pulled downward and then released, it vibrates vertically. The equation of motion is given by :

[tex]s=6cos\ t+3sin\ t[/tex]

Where

s is in centimeters

t is in seconds

Velocity of the particle, [tex]v=\dfrac{ds}{dt}[/tex]

[tex]v=\dfrac{d(6cos\ t+3sin\ t)}{dt}[/tex]

[tex]v=3cos\ t-6sin\ t[/tex]

Acceleration of the particle, [tex]a=\dfrac{dv}{dt}[/tex]

[tex]v=\dfrac{d(3cos\ t-6sin\ t)}{dt}[/tex]

[tex]v=-6cos\ t-3sin\ t[/tex]

Hence, this is the required solution.