Balance each of the following redox reactions occurring in basic solution.MnO−4(aq)+Br−(aq)→MnO2(s)+BrO−3(aq)Express your answer as a chemical equation.Identify all of the phases in your answer.

First we have to write into the two half-reactions.
Now balance the main atoms in the reaction.
Now balance the hydrogen and oxygen atoms on both the sides of the reaction.
If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.
If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion [tex](OH^-)[/tex] at that side where the less number of hydrogen are present.
Now balance the charge.

The half reactions in the basic solution are :

Reduction : [tex]MnO_4^-(aq)+2H_2O(l)+3e^-\rightarrow MnO_2(s)+4OH^-(aq)[/tex] ......(1)

Oxidation : [tex]Br^-(aq)+6OH^-(aq)\rightarrow BrO_3^-(aq)+3H_2O(l)+6e^-[/tex] .......(2)

Now multiply the equation (1) by 2 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

[tex]2MnO_4^-(aq)+Br^-(aq)+H_2O(l)\rightarrow 2MnO_2(s)+BrO_3^-(aq)+2OH^-(aq)[/tex]

nikitarahangdaleVT nikitarahangdaleVT · Answer 2 · 2022-03-15T08:27:25+01:00

Balanced redox reaction occurring in basic solution is 2MnO₄⁻(aq) + Br⁻(aq) + H₂O(aq) → 2MnO₂(s) + BrO₃⁻(aq) + 2OH⁻.

Those reaction in which oxidation and reduction process takes place simultaneously is know as redox reaction.

Given chemical reaction is:

MnO₄⁻(aq) + Br⁻(aq) → MnO₂(s) + BrO₃⁻(aq)

Steps to balance the redox reaction in the basic solution is as follow:

First we have to divide the whole reaction into the half reactions.
Then we will balance the each element on both sides except hydrogen and oxygen atom.
Then we will balance the oxygen atoms by adding H₂O molecules on that side where oxygen atoms are less.
Then we balance the hydrogen atoms by adding H⁺ ions.
Then we add OH⁻ on both sides to neutralize excess H⁺ ions.
Then we combine H⁺ & OH⁻ ions to make H₂O molecules and simply the reaction by cancelling excess H₂O molecules.
Then we balance the charges on both side of the reaction by adding electrons.
Then cross multiply the equations with the coefficient of the added electrons and then add the both reaction.
After adding simplify the reaction by cancelling out excess molecules.

Hence balanced reaction is 2MnO₄⁻(aq) + Br⁻(aq) + H₂O(aq) → 2MnO₂(s) + BrO₃⁻(aq) + 2OH⁻

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