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A television station claims that the amount of advertising per hour of broadcast time has an average of 14 minutes and a standard deviation equal to 2.4 minutes. You watch the station for 1​ hour, at a randomly selected​ time, and carefully observe that the amount of advertising time is equal to 8 minutes. Calculate the​ z-score for this amount of advertising time.

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JeanaShupp

Answer:  -2.5

Step-by-step explanation:

Given : A television station claims that the amount of advertising per hour of broadcast time has an average of 14 minutes and a standard deviation equal to 2.4 minutes.

i.e. [tex]\mu=14[/tex]

[tex]\sigma=2.4[/tex]

Let x be the random variable that represents the amount of advertising per hour.

The formula to find the z-score :-

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

For x= 8 , we have

[tex]z=\dfrac{8-14}{2.4}=-2.5[/tex]

Hence, the z-score for this amount of advertising time = -2.5

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