A small town has 800 inhabitants. At 8 AM, 120 people have heard a rumor. By noon half the town has heard it. At what time will 90% of the population have heard the rumor? (Do not round k in your calculation. Round the final answer to one decimal place.)

Respuesta :

Answer:

At what time will 90% of the population have heard the rumor?

The rumor was heard by 90% of the population in 5.9 hours or 5 hours and 54 minutes

So, at 1:54 pm, 90% of the population had heard the rumor.

Step-by-step explanation:

To resolve this exercise we need to know the exponential model:

[tex]P_(_t_)= P_0 *e^k^t[/tex] (1)

Where:

[tex]P_(_t_):[/tex] the quantity inhabitants in certain time who heard the rumor

[tex]P_0:[/tex] Initial people who heard the rumor

k: constant

t: time frame

We know in 4 hours ([tex]12-8=4[/tex] hours) half the town has heard the rumor because:

[tex]Half town= \frac{800}{2}=400[/tex] inhabitants

With this information we can find the constant (k), because we have all the information in [tex]t=4 hours[/tex]

[tex]P_(_4_)=[/tex] 400 people

[tex]P_0=[/tex] 120 people

t= 4 hours

When we replace in equation 1 we have:

[tex]400=120e^4^k[/tex]

[tex]\frac{400}{120} =e^4^k[/tex]

[tex]\frac{10}{3}=e^4^k[/tex]

We multiply by natural logarithm on both sides of this equation and we have:

[tex]Ln(\frac{10}{3} )= 4*k\\k=\frac{Ln(\frac{10}{3} )}{4}[/tex]

With the constant (k) we can find at what time 90% of the population have heard the rumor

[tex]800*0.9=720 people[/tex] (90% of the population)

So we have:

[tex]P_(_t_)=[/tex] 720 people

[tex]P_0=[/tex] 120 people

[tex]k=\frac{Ln\frac{10}{3}}{4}[/tex]

When we replace in equation 1 we have:

[tex]720=120*e^\frac{Ln\frac{10}{3} }{4} ^*^t[/tex]

[tex]\frac{720}{120}=e^\frac{Ln\frac{10}{3}}{4}^t\\6=e^\frac{Ln\frac{10}{3}}{4}^t[/tex]

We multiply by natural logarithm on both sides of this equation and we have:

[tex]Ln 6 = \frac{Ln\frac{10}{3}}{4}*t\\[/tex]  

[tex]4*Ln 6 = Ln\frac{10}{3}*t\\t=\frac{4*Ln 6 }{Ln\frac{10}{3}}[/tex]

[tex]t=\frac{4*1.79}{1.20} \\t=\frac{7.16}{1.20} \\t=5.9 hours[/tex]

We can find how many minutes are 0.9 hours:

[tex]0.9hours\frac{60 minutes}{1hour} = 54 minutes[/tex]

t= 5 hours and 54 minutes

Now, we know the rumor was heard by 90% of the population in 5.9 hours or 5 hours and 54 minutes

So, at 1:54 pm, 90% of the population had heard the rumor.