Respuesta :
f(n+1) = 10 (0.5)^(n+1)
f(n) = 10 (0.5)^n
rate = f(n+1)/f(n) = [10(0.5)^(n+1)] / 10(0.5)^n] = (0.5)^(n+1-n) = (0.5)^1 = 0.5
Answer: 0.5
f(n) = 10 (0.5)^n
rate = f(n+1)/f(n) = [10(0.5)^(n+1)] / 10(0.5)^n] = (0.5)^(n+1-n) = (0.5)^1 = 0.5
Answer: 0.5
The multiplicative rate of change of the function passing through ordered pairs (0, 10), (1, 5), and (2, 2.5), represented by the function f(x) = 10(0.5)ˣ is 2
What is an equation?
An equation is an expression that shows the relationship between two or more numbers and variables
The ordered pairs (0, 10), (1, 5), and (2, 2.5) can be represented by the function f(x) = 10(0.5)ˣ.
Hence the rate of change of the function = 0.5
The multiplicative rate of change of the function = 1/0.5 = 2
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