Answer:
The flashdrive can hold 35389 400-pages-books
Explanation:
If [tex]\frac{2}{3}[/tex] of a page occupies 1 kB of memory, we can calculate how much memory a book will take
[tex]2/3kB=1 page\\ x kB=400 pages\\266.67 kB=400 pages[/tex]
Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.
To do the calculation, we have to know how many kilobytes are in 9 gigabytes.
There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:
[tex]Memory_{in _kilobytes}^{} =1024\frac{kilobytes}{megabytes} *1024\frac{megabytes}{gigabytes}*9=9437184 kilobytes[/tex]
Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.
[tex]Books=\frac{Flash drive memory}{Filesize of a book} =\frac{9437184kilobytes}{266.67\frac{kilobytes}{book} } =35389,4 books[/tex]
The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.
