Answer:
16.197 seconds
Step-by-step explanation:
the time and the final place fot both cars is the same.
for the Boxster we have
X = Vboxster . T
being
X the distancance from the initial place of the Boxter to the meeting point
Vboxster the speed of the Boxster (26m/s)
T the time
and for the Scion
X = Xo + Vscion . T
Being
Xo the initial point of the Scion (115m)
X the distancance from the initial place of the Boxster to the meeting point
Vscion the speed of the Scion (18.9 m/s)
T the time
Xo + Vscion . T = Vboxster . T
Xo = Vboxster . T - Vscion . T
Xo = (Vboxster - Vscion) . T
Xo/(Vboxster - Vscion) = T
115m/ (26-18.9) m.s-1 = T
16.197 s = T
Answer:
a)t = 16.2s : time it takes for the Boxster to catch the Scion
b)The displacement of the Boxster (db) is 115 m more than the displacement of the Scion(ds)
db =ds+115
Step-by-step explanation:
Conceptual analysis
We apply the formula for constant speed movement:
v= d/t Formula (1)
v = speed in m/s
d: distance in m
t: time in s
Problem development
The time of Scion (ts) is equal time of Boxster (tb)
t (s) =tb=t
The displacement of the Boxster is 115 m more than the displacement of the Scion
db =ds+115
we apply formula (1 )car kinematics :
Scion kinematics
18.9=ds/t
t =ds /18.9 Equation (1)
Boxster kinematics
26=db/t
26=(ds+115)/t
t=(ds+115)/26 Equation (2)
Equation (1) = Equation (2)
ds /18.9 =(ds+115)/26
18.9(ds+115)= 26 ds
18.9ds+18.9*115=26 ds
2173.5= 26 ds-18.9ds
2173.5=7.1ds
ds =2173.5÷7.1
ds=306.12m
We replace ds=306.12m in the equation (1)
t =306.12÷18.9
t = 16.2s
