Answer:
B) μD = 0.60 ± 0.10(1.397)
Step-by-step explanation:
The confidence interval is given by:
[tex]MD±t_{\alpha/2, n-1} \frac{s}{\sqrt{n} }[/tex]
Where
MD=60
n=9
df=n-1=8
[tex]t_{\alpha/2, n-1}=1.397[/tex]
[tex]s=\sqrt{0.09} =0.3[/tex]
Then the confidence interval is
μD=0.60±1.397*(0.3/√9)
μD=0.60±0.10*(1.397)