Answer:
[tex]y = \frac{1}{3} x -1[/tex]
Step-by-step explanation:
1. find the slope that includes the points (-3,-2) and (3,0)
[tex]\frac{y2-y1}{x2-x1} =m[/tex] ->slope
0-(-2)/3-(-3) = [tex]\frac{2}{6} (simplify) = \frac{1}{3}[/tex]
2. find the y-intercept
[tex]y = mx +b[/tex] -> slope-intercept form
plug in the y-coord. and the x-coord along with the slope you found (or rather I found) and solve. It could be from either coordinate given.
[tex]0=\frac{1}{3} (3)+b[/tex]
3. solve.
[tex]0 = 1 +b[/tex]
[tex]-1 = b[/tex]
4. write the equation with the slope and y-int you found and voila!
