Answer:
[tex]2^{85}-1[/tex]
Explanation:
Considering the number are stored using binary notations.
If there are total 86 bits and 1 bit is used as sign bit. Then in total one can have [tex]2^{85}[/tex] bit combinations since a bit can be either stored as 0 or as 1.
Therefore, the largest number that can be stored will be [tex]2^{85}-1[/tex].
To understand it in better way let's scale down the problem to 3 bits representation. The largest number that can be stored using 3 bits is 111 which in decimal form is 7 and is equal to [tex]2^{3}-1[/tex].
