Answer:
λ=3,λ=1
Step-by-step explanation:
let (λ-2)=a
[tex]ax + y = 0\\x + ay = 0[/tex]
solve:
[tex]ax + y = 0\\ax + a^2y = 0\\y-a^2y=0\\a^2 = 1[/tex]
replace a:
[tex](\lambda-2)^2=1\\\lambda^2-4\lambda+4=1\\\lambda^2-4\lambda+3=0[/tex]
solve:
[tex]\lambda_1=2+\sqrt{4-3} =3\\\lambda_2=2-\sqrt{4-3}=1[/tex]