Answer:
3.2 m/s²
Explanation:
Initial velocity of the red blood cell = 0 m/s = u
Initial velocity of the red blood cell = 0.8 m/s = v
Time taken by the red blood cell to reach its final velocity = 250 ms = t
Equation of motion
[tex]v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{0.8-0}{250\times 10^{-3}}\\\Rightarrow a=3.2\ m/s^2[/tex]
Average acceleration of a red blood cell as it leaves the heart is 3.2 m/s²