Answer:
Explanation:
Conduction of heat per second Q through a metal sheet having thermal conductivity K , thickness d , area A and temperature difference between cold and hot surface ( T₂ -T₁ ) is given by the following equation
Q = [tex]\frac{KA(T_2-T_1)}{d}[/tex]
Area A = π R² = 3.14 X 10000 X 10⁻⁶
= 3.14 X 10⁻2 m²
For aluminium plate :-
T₂ - T₁ = [tex]\frac{Q\times d}{KA}[/tex]
= [tex]\frac{600\times5\times10^{-3}}{240\times3.14\times10^{-2}}[/tex]
T₂ - T₁ = .4
T₂ = 110.4 ° C
For copper plate :
[tex][tex]\frac{600\times5\times10^{-3}}{390\times3.14\times10^{-2}}[/tex][/tex]
T₂ - T₁ = .25
T₂ = 110.25 ° C
