⇒Given equation of line Passing through (–7, 11) and (8, –9) is given by
[tex]y-11= \frac{-4}{3}(x+7)[/tex]
⇒Equation of line Passing through (–7, 11) and (8, –9) is given by
[tex]\rightarrow \frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\\rightarrow \frac{y-11}{x-(-7)}=\frac{-9-11}{8-(-7)}\\\\\rightarrow \frac{y-11}{x+7}=\frac{-20}{15}\\\\\rightarrow \frac{y-11}{x+7}=\frac{-4}{3}\\\\\rightarrow 3y-33=-4x-28\\\\\rightarrow 4x+3y=33-28\\\\ \rightarrow 4x+3y=5[/tex]
Option C
4x+3y=5
