Answer:
The probability that a surviving passenger belongs to second-class cabin passengers is [tex]\frac{118}{285} = 0.414[/tex]
Step-by-step explanation:
Let's define the events:
S: The passenger survived.
NS: The passenger did NOT survive.
C2: The passenger belonged to a second class cabin.
NC2: The passenger did not belong to a second class cabin.
With these events and the information provided the probability are:
[tex]P (S) = 711/2201[/tex]
[tex]P(NS) = 1490/2201[/tex]
[tex]P(C2) = 285/2201[/tex]
[tex]P (NC2) = 1495/2201[/tex]
The probability that a surviving passenger belongs to second-class cabin passengers is:
[tex]P (S | C2) = \frac{P(S\bigcapC2)}{P(C2)} = \frac{\frac{118}{2201}}{\frac{285}{2201}} = \frac{118}{285} = 0.414[/tex]