Answer: 7.66 8 m/s
Explanation:
Since the squirrel fell out and it is not thrown, we assume the initial velocity is zero ([tex]V_{o}=0[/tex]). On the other hand, the squirrel only experiences the acceleration due gravity, which is constant and in the downward direction [tex]g=-9.8 m/s^{2}[/tex]. So, the following equation will be useful to find the squirrel's final velocity [tex]V_{f}[/tex]:
[tex]{(V_{f})}^{2}={(V_{o})}^{2}-2gd[/tex]
Where [tex]d=3 m[/tex] is the height from which the squirrel fell
As [tex]V_{o}=0[/tex]:
[tex]{(V_{f})}^{2}=-2gd[/tex]
Then:
[tex]{(V_{f})}^{2}=-2(-9.8 m/s^{2})(3 m)[/tex]
[tex]V_{f}=\sqrt{58.8 m^{2}/s^{2}}[/tex]
Finally:
[tex]V_{f}=7.668 m/s[/tex]
