Answer:
A. The final pressure at the tire would be 476 kPa
Explanation:
Since the volume is constant the ideal gas equation would be used to obtain the final pressure at the tire.
Given
the initial temperature [tex]T_{1}[/tex] = 288 K
the initial pressure [tex]P_{1}[/tex] = 460 k Pa
the final temperature [tex]T_{2}[/tex] = 298 K
the final pressure [tex]P_{2}[/tex] = ?
Using the ideal gas equation;
PV = nRT
[tex]P_{1}[/tex] / [tex]T_{1}[/tex] = [tex]P_{2}[/tex] / [tex]T_{2}[/tex]
Making [tex]P_{2}[/tex] the subject formula
[tex]P_{2}[/tex] = ([tex]P_{1}[/tex] x [tex]T_{2}[/tex] ) / [tex]T_{1}[/tex]
[tex]P_{2}[/tex] = (460 x 298) / 288
[tex]P_{2}[/tex] = 475.972 kPa
[tex]P_{2}[/tex] ≈ 476 kPa
Therefore the final pressure at the tire would be 476 kPa
