Answer:y=4/3
y is directly proportional to x^2 is written as
[tex]y \alpha {x}^{2} [/tex] introducing a constant,
y=kx^2
but from the question, when y=2 , x=3 . putting it in the formula to get the value of k
[tex]2 = {3}^{2} \times k[/tex]
2=9k . dividing through by 9 to get the value of k
[tex] \frac{2}{9} = \frac{9k}{9} [/tex]
[tex]k = \frac{2}{9} [/tex]
putting it in the general expression
[tex]y = \frac{2}{9} x[/tex]
the value of y when x=6
[tex]y = \frac{2}{9} \times 6[/tex]
[tex]y = \frac{4}{3} [/tex]
therefore the value of y when x=6 is
4/3
