Select the correct interpretation of the probability of getting an 11 when a pair of dice is rolled. Interpret an event as significant if its probability is less than or equal to 0.05.

We are considering that we have 2 dices with 6 faces each (so, the probability to gettig any face in any dish is 1/6). To get an 11, we only have two ways to obtain it:

Dice 1= 6 and Dice 2 =5

or

Dice 1= 5 and Dice 2 =6

So, the probability of the event is given as:

P(Dice1=5 ∧ Dice2=6) ∪ P(Dice1=6 ∧ Dice2=5) = P(Dice1=5) x P(Dice2=6) + P(Dice1=6) x P(Dice2=5) = 1/6 x 1/6 + 1/6 x 1/6 = 1/36 + 1/36 = 2/36 = 1/18.

As 1/18 = 0,055, and 0,055 > 0,05, we consider the event as not significative (according to the definition of significance in the sentence).

facundo3141592 facundo3141592 · Answer 2 · 2020-04-10T02:30:14+02:00

Answer:

When you throw a dice, the total number of options that you can get is the product of the number of options for each dice, this means that the total number of combinations is:

c = 6*6 = 36 combinations.

Now, the combinations where the dice add to 11 are:

5 in one dice and 6 in the other.

6 in one dice and 5 in the other.

so out of 36 combinations, we have 2 options where we have an 11.

then the probability is the combinations that add to 11 divided by the total number of combinations:

p = 2/36 = 1/18 = 0.056

the probability is greater than 0.05, so it is significant.