Answer:
56.7°
Explanation:
Imagine a rectangle triangle.
The triangle has 3 sides.
One side is the height of the tower, let's name it A.
Another side is the distance from the base of the tower to the point where the waire touches the ground. Let's name that B.
Sides A and B are perpendicular.
The other side is the length of the wire. Let's name it C.
From trigonometry we know that:
cos(a) = B / C
Where a is the angle between B anc C, between the wire and the ground.
Therefore
a = arccos(B/C)
a = arccos(552/1005) = 56.7°
[tex]56.7^\circ[/tex] angle the wire makes with the ground.
Given :
A guy wire 1005 feet long is attached to the top of a tower.
When pulled taut, it touches level ground 552 feet from the base of the tower.
Solution :
We know that,
[tex]\rm cos \theta = \dfrac{Base}{Hypotanuse}[/tex]
Given that,
base = 552 ft
hypotanuse = 1005 ft
Therefore,
[tex]\rm cos\theta = \dfrac{552}{1005}[/tex]
[tex]\rm \theta = cos^-^1 \dfrac{552}{1005}[/tex]
[tex]\theta = 56.7^\circ[/tex]
[tex]56.7^\circ[/tex] angle the wire makes with the ground.
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https://brainly.com/question/22798381?referrer=searchResults
