Answer:
The magnitude of the charge q is 3.45 x 10^-7.
Explanation:
To solve this problem you have to used the Second Newton´s Law and Coulomb Law.
F = mxa (Newton) and F = k x (q1 x q2)/r² (Coulomb)
where a = aceleration, k= Coulomb constant= 9,8 x 10^9 N.m²/C²
r=distance between particules and q1 and q2 are the charges.
If we equal both equations we have
mxa = k x (q1 x q2)/r² ⇒ [(m1 + m2) x a x r²]/k = q1 x q2.
As m1 = m2 = m and q1 = q2 = q ⇒ (2m x a x r²)/k = q²
Finally, √[(2m x a x r²)/k] = q
Replacing with the information given in the problem.....
q= √[((0,013 kg) x (100 m/s²) x (0,03 m)²)/ 9.8 x 10^9 N.m²/C²
⇒ q = 3.45 x 10^-7 C.
