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supply 5 N∙m of torque to a bolt located at the origin using a wrench that lies along the positive yy-axis. Assume the bolt head is at the origin and the threaded portion of the bolt lies along the negative xx-axis. If you apply a 25 N force at the end of the wrench in the direction 2???????? − 3????????, what length of wrench would be required to supply the desired torque? Under this force are we tightening or loosening the bolt?

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klefenz

Answer:

Explanation:

We need to supply 5 Nm to the bolt.

If we have a force of 25 N in the direction (2*i - 3*j), the torque is related to the length of the wrench.

T = F * d

d = T / F

d = 5 / 25 = 0.2 m

Assuming the wrench is perpendicular to the force.

The vector of the force is:

[tex]F = 25 N \frac{2i - 3j}{\sqrt{2^2 + (-3)^2}} = 13.9i - 20.8[/tex]

This is a countr-clockwise direction. If the bolt is right handed (most are) we are tightening it.

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