Answer:
The coordinates of point H' are (-2 , 0) ⇒ answer B
Step-by-step explanation:
* Lets revise the vertical stretch
- A vertical stretching is the stretching of the graph away from the
x-axis
- If k > 1, then the graph of y = k • f(x) is the graph of f(x) vertically
stretched by multiplying each of its y-coordinates by k
* Lets solve the problem
- Square EFGH stretches vertically by a factor of 2.5 to create
rectangle E′F′G′H′
∴ k = 2.5
- The square stretches with respect to the x-axis
∴ The square stretches vertically
∴ The y-coordinates of each vertex of the square EFGH are
multiplied by 2.5 to get the vertices of the rectangle E'F'G'H'
∵ Point H located at (-2 , 0)
∵ The image of point (x , y) after stretched vertically by k is (x , ky)
∴ Point H' located at (-2 , 0 × 2.5) ⇒ (-2 , 0)
∴ The coordinates of point H' are (-2 , 0)
∴ Point H' located at (-2 , 0)
