Sam makes a deposit at the bank which is comprised of $5, $10, and $20 bills. If the number of $5 bills is three more than the number of $10 bills, the number of $20 bills is half the number of $5 bills, and his total deposit is $270, how many bills of each type did he deposit?

Respuesta :

Answer:

Number of $5 bills= 12

Number of $10 bills= 9

Number of $20= 6

Explanation:

Giving the following information:

Total deposit= $270

$5 bills are three more than the number of $10 bills.

The number of $20 bills is half the number of $5 bills.

x1= number of $5 bills

x2= number of $10 bills

x3= number of $20 bills

x1=3+x2

x3=x1/2

The function to calculate the number of bills is:

Total number of bills= (3+x2)*$5 + x2*$10+ (x1/2)*$20

n $x1 n $x2 n $x3  

4 20 1 10 2 40 70

5 25 2 20 2,5 50 95

6 30 3 30 3 60 120

7 35 4 40 3,5 70 145

8 40 5 50 4 80 170

9 45 6 60 4,5 90 195

10 50 7 70 5 100 220

11 55 8 80 5,5 110 245

12 60 9 90 6 120 270

x1= 12

x2= 9

x3=6