Answer:
10 m/s
Explanation:
u = 20 m/s
v = 0 m/s
t = 5.8 s
Let a be the acceleration and s be the distance traveled by the car in time t.
use first equation of motion
v = u + a t
0 = 20 + a x 5.8
a = -3.45 m/s^2
Use third equation of motion
[tex]v^{2}=u^{2}+2as[/tex]
[tex]0^{2}=20^{2}-2 \times3.45 \times s[/tex]
s = 58 m
The average speed is defined as the ratio of distance traveled to the time taken.
[tex]Average speed = \frac{58}{5.8} = 10 m/s[/tex]
thus, the average speed of the car is 10 m/s.
