Respuesta :
Answer:
B. 54π yd^2
Step-by-step explanation:
On god it is right trust mee!
Answer: Our required area is 54π sq. yd.
Step-by-step explanation:
Since we have given that
Diameter of an ice skating = 44 feet
Radius of an ice skating = 22 feet
as we know the formula for area :
Area would be
[tex]\pi r^2\\\\=\pi \times 22^2\\\\=484\pi\ ft^2[/tex]
As we know that
9 sq ft = 1 sq yd
So, it becomes,
[tex]\dfrac{484\pi}{9}=53.77\pi\ yd^2\approx 54\pi\ yd^2[/tex]
Hence, our required area is 54π sq. yd.
