Answer:
The factors of x^2+3x-4 are (x-1)(x+4) ....
Step-by-step explanation:
We have to find the factors of x^2+3x-4
As we know that this is a quadratic equation.
So we have to find the roots first.
The roots are -1 and 4.
Now completing the quadratic formula using the roots we have :
x^2+4x-x-4
Make a pair of first two terms and last two terms:
(x^2+4x)-(x+4)
Now take out the common from each pair:
x(x+4)-1(x+4)
(x-1)(x+4)
Thus the factors of x^2+3x-4 are (x-1)(x+4) ....
