Answer:
Roots are complex numbers
Step-by-step explanation:
we know that
In a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex]
The discriminant is equal to [tex]b^{2} -4ac[/tex]
If [tex]b^{2} -4ac=0[/tex] -----> The equation has only one real root
If [tex]b^{2} -4ac>0[/tex] -----> The equation has two real roots
If [tex]b^{2} -4ac<0[/tex] -----> The equation has complex roots
In this problem the discriminant is -8
so
-8 < 0
therefore
Roots are complex numbers
