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The concrete slab of a basement is 11 m long, 8 m wide, and 0.20 m thick. During the winter, temperatures are nominally 17°C and 10°C at the top and bottom surfaces, respectively. If the concrete has a thermal conductivity of 1.4 W/m · K, what is the rate of heat loss through the slab? If the basement is heated by a gas furnace operating at an efficiency of ηf = 0.9

Respuesta :

Answer:

[tex]\frac{dQ}{dt}= 4312 W[/tex]

Explanation:

As we know that base of the slab is given as

[tex]A = 11 \times 8[/tex]

[tex]A = 88 m^2[/tex]

now we know that rate of heat transfer is given as

[tex]\frac{dQ}{dt} = \frac{kA}{x} (T_2 - T_1)[/tex]

here we know that

[tex]k = 1.4 W/m k[/tex]

Also we have

[tex]x =0.20[/tex]

[tex]\frac{dQ}{dt} = \frac{1.4(88)}{0.20}(17 - 10)[/tex]

[tex]\frac{dQ}{dt}= 4312 W[/tex]

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