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Let's say A keep tossing a fair coin, until he get 2 consecutive heads, define X to be the number of tosses for this process; B keep tossing another fair coin, until he get 3 consecutive heads, define Y to be the number of the tosses for this process. 1) Calculate P{X>Y}

Respuesta :

A=Tossing a  fair coin, until getting  2 consecutive heads,

Minimum Number of tosses

 =(SF)(FS)(FF)(SS)

X =8 tosses

S=Success

F=Failure

B=Tossing a  fair coin, until getting 3 consecutive heads.

Minimum Number of tosses

 =(SFS)(FSS)(SSF)(SFF)(FSF)(FFS)(FFF)(SSS)

Y =24 Tosses

Probability of an event

        [tex]=\frac{\text{Total favorable Outcome}}{\text{Total Possible Outcome}}\\\\P(X)=\frac{SS}{8}\\\\P(X)=\frac{2}{8}\\\\P(X)=\frac{1}{4}\\\\P(Y)=\frac{SSS}{24}\\\\P(Y)=\frac{3}{24}\\\\P(Y)=\frac{1}{8}\\\\\frac{1}{4}> \frac{1}{8}\\\\P(X)>P(Y)[/tex]

               

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