Answer:
[tex]V = 12.85 cm^3[/tex]
Explanation:
As we know that initially the air bubble is at depth 110 m
so the pressure of the air bubble is given as
[tex]P = P_o + \rho gh[/tex]
[tex]P = 1.01 \times 10^5 + (1000)(9.81)(110)[/tex]
[tex]P = 1.18 \times 10^6 Pa[/tex]
initial volume of the bubble is given as
[tex]V = 1.1 cm^3[/tex]
now we know that here temperature of air bubble is constant
so we have
[tex]P_1 V_1 = P_2 V_2[/tex]
[tex](1.18 \times 10^6)(1.1 cm^3) = (1.01 \times 10^5) V[/tex]
[tex]V = 12.85 cm^3[/tex]
