If a glass is knocked off of a table that is 2.6 m tall, how long does it take for the glass to hit the ground? FILL IN All GUESS STEPS TO GET CREDIT. CHECK EXAMPLE PROBLEM BELOW.

Respuesta :

Answer:

0.73 s

Explanation:

The glass is in free fall, so its vertical position at time t is given by the equation:

[tex]y(t) = h + ut + \frac{1}{2}gt^2[/tex]

where

h = 2.6 m is the initial height

u = 0 is the initial velocity of the glass

[tex]g=-9.8 m/s^2[/tex] is the acceleration of gravity (downward since it is negative)

We want to know the time t at which the glass reaches the ground, so when

y(t) = 0

So the equation becomes

[tex]0 = h + \frac{1}{2}gt^2[/tex]

And solving for t, we find

[tex]t=\sqrt{\frac{-2h}{g}}=\sqrt{\frac{-2(2.6)}{-9.8}}=0.73 s[/tex]

Answer:

0.73 sec

Explanation:

formula:X=ViT+(0.5)AT^2

2.6=(0)T+(0.5)(9.8)T^2

cancel:(0)T

2.6=(0.5)(9.8)T^2

take 0.5 to other side and divide with 2.6

5.2=(9.8)T^2

now do the same with 9.8

0.530612 and square root it because u can't leave the T^2

you'll get t=0.73 s