Answer:
The distance travelled is 151.22m and it took 0.97s
Explanation:
Well, this is an ARM problem, so we will need the following formulas
[tex]x(t)=x_{0} +v_{0} *(t-t_{0} )+0.5*a*(t-t_{0} )^{2}[/tex]
[tex]v(t)=v_{0} +a*(t-t_{0} )[/tex]
where [tex]x_{0}[/tex] is the initial position (we can assume is zero), [tex]v_{0}[/tex] is the initial speed of 104 m/s, [tex]t_{0}[/tex] is the initial time (we also assume is zero), a is the acceleration of 107 m/s2, v is speed, x is position and t is time.
Now that we have the formulas, we know that when the electron stops it has no speed. Then we calculate how much time it takes to stop.
[tex]0=104m/s-107m/s^{2} *t\\t=0.97s[/tex]
Finally, we calculate the distance travelled in this time
[tex]x(0.97s)=104m/s*0.97s+0.5*107m/s^{2}*(0.97s)^{2}=151.22m[/tex]
Answer:
Part a)
[tex]d = 5 m[/tex]
Part b)
[tex]T = 2\times 10^{-3} s[/tex]
Explanation:
Part a)
The electron will move in this forbidden region till its speed will become zero
So here we will have
[tex]v_f = 0[/tex]
[tex]v_i = 10^4 m/s[/tex]
also its deceleration is given as
[tex]a = - 10^7 m/s^2[/tex]
so we will have
[tex]v_f^2 - v_i^2 = 2 a d[/tex]
[tex]0 - (10^4)^2 = 2(-10^7) d[/tex]
[tex]d = 5 m[/tex]
Part b)
Now the time till its speed is zero
[tex]v_f - v_i = at[/tex]
[tex]0 - 10^4 = -10^7 t[/tex]
[tex]t = 10^{-3} s[/tex]
so total time that it will be in the region is given as
[tex]T = 2 t[/tex]
[tex]T = 2\times 10^{-3} s[/tex]
