Answer:
7.41 x 10^-10 J
Explanation:
m = 4.5 kg
M = 6.3 kg
d = 1.7 m
The formula for the gravitational potential energy is given by
[tex]U = \frac{-GMm}{d}[/tex]
Where, G is the Universal gravitational constant
G = 6.67 x 10^-11 Nm^2/kg^2
[tex]U = \frac{-6.67 \times 10^{-11}\times 6.3 \times 4.5}{1.7}[/tex]
U = - 1.112 x 10^-9 J
Now the separation is tripled, d' = 3 x d = 3 x 1.7 m = 5.1 m
Let the potential energy is U'
The formula for the gravitational potential energy is given by
[tex]U' = \frac{-GMm}{d'}[/tex]
Where, G is the Universal gravitational constant
G = 6.67 x 10^-11 Nm^2/kg^2
[tex]U' = \frac{-6.67 \times 10^{-11}\times 6.3 \times 4.5}{5.1}[/tex]
U' = - 3.71 x 10^-10 J
the work done is equal to the change in potential energy
W = U' - U
W = - 3.71 x 10^-10 + 1.112 x 10^-9
W = 7.41 x 10^-10 J
